The Infinity Coil

When I was working on the many forms of the Robert Adams motor in the 1990’s , I was happy to fulfill the basic tenants of the original Robert Adams design. The clear revelations of a simple switched reluctance motor with parametric amplification factors that can go into resonance with itself and the larger environment gave me inspiration in the form of a double coil in the figure eight with two rotors running in opposite directions and two sets of pulse coils.

After many years I decided to return back to these designs as they merit greater experimentation. The original Infinity coils were two solenoids in parallel wound in a figure eight fashion, this would also work on two toroids stacked in parallel also adding the bifilar winding scheme, this became my final design as shown below.

As to the functionality of this coil, I put together a simple pulse circuit, that only uses a 0.5-3volt source and lights a MR16 3W light for about 10 hours beginning at 60% illumination, as shown below.

There is still more work that has been done on this arrangement as all relevant factors are notated in my up coming book ( “Talking with the Birds”) and have been explored to a greater degree than presented here. Regards Arto

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3 Responses to “The Infinity Coil”

  1. Multi-Filar Coils | Artojh's Renderings Says:

    […] Articles by Arto weblog « The Infinity Coil Synthonyms II […]

    Like

  2. Hao Cai Says:

    This is awesome, your COP is about 6.9. Very impressive.
    http://www.allaboutbatteries.com/Energy-tables.html
    I find a battery table in the above website. Use a the energy formula. since a typical alkaline long-life battery store 2.6 wh. You said that you have 60% illumination. so I use 3W*0.6*10h=18wh. This is your energy output divided by input which is 2.6wh. Guess what, You prove the free energy. cop=18/2.6=6.923 Great Job!! I like it.

    Like

    • artojh Says:

      Hi Hao,
      Thanks for the nice comments, as for this light lets put it into an expanded explanation.

      As per your calculation

      3 watts x 0.6 light output x 10 hours = 18 watt hours

      it should be

      3 x 0.6 x 10 x 0.25 Duty cycle = 4.5 watt hours

      accounting for the blocking oscillator duty cycle of approx 25%

      It still looks suspicious to me, remember I said with 60% illumination, this was at the start of the run, at the 5 hour mark it was closer to 15%, this means it was running down just like all batteries do. Here is the new equation, a bit closer to the observations at the end of the run.

      Let H = 1/sqrt(2) = reduction of illumination per hour

      3 x 0.6 x H^0 x 0.25 = 0.450 1st hour
      3 x 0.6 x H^1 x 0.25 = 0.318 2nd hour
      3 x 0.6 x H^2 x 0.25 = 0.225 3rd hour
      3 x 0.6 x H^3 x 0.25 = 0.159 4th hour
      3 x 0.6 x H^4 x 0.25 = 0.112 5th hour
      3 x 0.6 x H^5 x 0.25 = 0.079 6th hour
      3 x 0.6 x H^6 x 0.25 = 0.056 7th hour
      3 x 0.6 x H^7 x 0.25 = 0.039 8th hour
      3 x 0.6 x H^8 x 0.25 = 0.028 9th hour
      3 x 0.6 x H^9 x 0.25 = 0.020 10th hour

      This gives a total of 1.488 far from 18

      The COP the becomes 1.488/2.6 = 0.5724 this looks more realistic.

      Thanks for your input on this matter, the complete explanation is in my new book soon to be released, regards Arto

      Liked by 1 person

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